Standard To Vertex Form Calculator
Give this calculator any quadratic in standard form y = ax² + bx + c and it converts it to vertex form y = a(x − h)² + k, showing every completing-the-square step with your exact numbers, including clean fractions where the decimals are messy. It also runs in reverse (vertex form to standard form), and draws the parabola with the vertex, axis of symmetry, and both intercepts marked, so you can see the algebra and the geometry side by side.
| Standard form | |
| Vertex form | |
| Vertex (h, k) | |
| Axis of symmetry | |
| Direction | |
| Minimum / maximum value | |
| y-intercept | |
| x-intercepts |
Values print at 4 decimals; the working steps show the exact fractions (for example 2 rather than 2.0000) wherever they come out clean. The graph tab draws the same parabola with the vertex, axis and intercepts marked.
Click Calculate first, then open this tab to see the parabola with its vertex, axis of symmetry, x-intercepts and y-intercept marked.
Quick Answer
To convert y = 2x² − 8x + 6 to vertex form, complete the square: y = 2(x − 2)² − 2. The vertex is (2, −2), the axis of symmetry is x = 2, and because the parabola opens upward, −2 is the minimum value. The y-intercept is (0, 6) and the x-intercepts are (1, 0) and (3, 0). Enter your own a, b and c above to get the same breakdown for any quadratic.
Key takeaways
- Vertex form y = a(x − h)² + k puts the turning point (h, k) on the page: read it straight off, no solving needed.
- The two formulas do all the work: h = −b / 2a and k = c − b² / 4a, derived once by completing the square.
- The sign of a fixes the direction: positive opens upward with a minimum at the vertex, negative opens downward with a maximum.
- The axis of symmetry x = h always passes through the vertex, and the y-intercept of the standard form is always (0, c).
- The x-intercepts come from the discriminant b² − 4ac: two when it is positive, one (at the vertex) when zero, none when negative.
- Quick Answer
- How to use the standard to vertex form calculator
- The conversion formula: completing the square
- Worked example: y = 2x² − 8x + 6
- Going the other way: vertex form to standard form
- Why vertex form is the useful one for real problems
- What competing calculators miss
- Frequently asked questions
- Add This Calculator to Your Website
- References
How to use the standard to vertex form calculator
Enter three coefficients, click Calculate, and read the conversion. The results stay hidden until you calculate, and a, b, c come pre-filled with the worked example below so the first click shows you the full output.
- Pick the conversion direction: "Standard form to vertex form" for y = ax² + bx + c, or "Vertex form to standard form" to expand y = a(x − h)² + k back out. The input boxes switch to match.
- Enter your numbers: decimals and fractions work fine (try 2.5 or −1/3 style decimals like 0.3333). The tool refuses a = 0 with an explanation, since ax² + bx + c with a = 0 is a line, not a parabola.
- Read the result table: vertex form first and largest, then the vertex point, axis of symmetry, direction, the minimum or maximum value, the y-intercept, and the x-intercepts with their count.
- Check the working: the numbered steps show the completing-the-square arithmetic with your exact numbers, including clean fractions (2 rather than 2.0000) where they come out exact. Open the Graph tab to see the same parabola drawn with the vertex, axis and intercepts marked.
The conversion formula: completing the square
Standard form y = ax² + bx + c becomes vertex form y = a(x − h)² + k through completing the square, and the two formulas below fall out of that one derivation. They are the same formulas that Wolfram MathWorld's completing-the-square page derives from the general quadratic, and they power every vertex calculation on this page.
k = c − b² / 4a
y = a(x − h)² + k
The idea behind them is simple: factor a out of the x terms, take half the x-coefficient inside the parentheses, square it, and add and subtract it so nothing changes. That creates a perfect square (x + b/2a)² and leaves a leftover constant that becomes k. The calculator's steps show each move with your numbers; if you want to practice the method itself rather than convert one equation, the completing the square calculator works through the technique on its own terms.
Worked example: y = 2x² − 8x + 6
With a = 2, b = −8, c = 6 pre-filled, one click gives: vertex form y = 2(x − 2)² − 2, vertex (2, −2), axis x = 2, minimum value −2 at x = 2, y-intercept (0, 6), and two x-intercepts at (1, 0) and (3, 0). Every number below is exactly what the tool prints.
Check it by substitution: at x = 2, y = 2(4) − 16 + 6 = −2, which is the vertex, and 2(1)² − 8(1) + 6 = 0 confirms the intercept (1, 0). The same arithmetic, run on four more real inputs, gives the checks below. Type any row in to reproduce it exactly.
| Standard form (a, b, c) | Vertex form | Vertex | x-intercepts |
|---|---|---|---|
| y = x² − 6x + 5 | y = (x − 3)² − 4 | (3, −4) | (1, 0) and (5, 0) |
| y = −3x² + 6x + 1 | y = −3(x − 1)² + 4 | (1, 4), maximum | (2.1547, 0) and (−0.1547, 0) |
| y = x² + 2x + 1 | y = (x + 1)² | (−1, 0), touches axis | (−1, 0) only |
| y = x² + 4 | y = x² + 4 | (0, 4), minimum | none (never crosses) |
Notice how the third row behaves when the discriminant b² − 4ac equals zero: the vertex form collapses to a bare square y = (x + 1)², the single x-intercept sits exactly at the vertex, and the parabola just touches the axis. That is the visual meaning of a repeated root, and the graph tab makes it obvious at a glance.
Going the other way: vertex form to standard form
Expanding y = a(x − h)² + k back to standard form is ordinary algebra: square the binomial, multiply through by a, and collect. The calculator does it as b = −2ah and c = ah² + k, which is exactly what expanding gives: a(x² − 2hx + h²) + k = ax² − 2ahx + (ah² + k).
Try it with the reverse of the worked example: a = 2, h = 2, k = −2 expands to y = 2x² − 8x + 6, the exact standard form we started with. Round-tripping like this is the fastest sanity check on any conversion tool: feed the answer back through the other direction and the original equation should come out. Purplemath's vertex-form page walks the same expansion by hand if you want to see the algebra in textbook form.
Why vertex form is the useful one for real problems
Standard form answers "what is y when x is this?", but vertex form answers "where is the best point?" That makes it the natural form for optimization. A ball's height h(t) = −16t² + 64t + 5 converts to vertex form with vertex at (2, 69): maximum height 69 feet at t = 2 seconds, no calculus needed. Revenue as a function of price is often quadratic too, and the vertex of R(p) = −100p² + 5000p gives the revenue-maximizing price directly.
It also makes transformations visible. y = (x − 3)² + 2 is the plain parabola shifted 3 right and 2 up; y = −2(x − 3)² + 2 is the same curve flipped, stretched by a factor of 2, and moved. Each parameter in vertex form maps to one geometric move, which is why graphing from vertex form is a sketch of four facts: vertex, axis, direction, and width. For the wider polynomial picture beyond quadratics, the polynomial calculator handles higher-degree expressions.
What competing calculators miss
Vertex form tools fall into two camps, and each leaves something out:
- Converter-only tools (calculator-online.net, calculatored.com): convert both directions and show a graph, but the working stops at the answer. Students copy the result without seeing the completing-the-square steps, which is precisely the algebra the homework is testing.
- Kitchen-sink tools (calculator.now, acalculator.co.uk): accept standard, vertex, factored and even three-point input, but spread thin: the example walkthroughs are sparse and the geometry (what h and k actually mean for the graph) gets a paragraph at most.
- The richest free tool (onlycalculators.com): to its credit, it shows focus, discriminant and a full x/y table with numbered working, which is why it is the benchmark to beat. Its worked example (y = (x − 3)² − 4 from x² − 6x + 5) agrees with this calculator's own checks table to the decimal.
- Sloppy tutorial content (a dev.to walkthrough in the results): its projectile example claims h = −3 for h(t) = −16t² + 64t + 5 while also saying the maximum is at t = 2 seconds, which contradict each other (the vertex is at t = 2). Copy-paste algebra errors like that are why checking with a tool matters.
- The gap this page fills: both conversion directions, the numbered completing-the-square working with exact fractions, the discriminant-classified x-intercepts, the minimum/maximum reading, and a labelled graph, all verified against each other on the same page. No tool in the results shows the fraction-exact step and the decimal-exact step side by side the way the steps table here does.
Frequently asked questions
Vertex form is y = a(x − h)² + k, a way of writing a quadratic so the vertex (h, k) is visible at a glance. The value a controls the width and direction of the parabola, h shifts it left or right, and k shifts it up or down.
Complete the square: factor a out of the x terms, take half of the x-coefficient inside the parentheses, square it, add and subtract it, then factor the perfect square and collect the constants. For y = 2x² − 8x + 6, that gives y = 2(x² − 4x) + 6 = 2[(x − 2)² − 4] + 6 = 2(x − 2)² − 2.
Expand the square and multiply through: y = a(x − h)² + k becomes y = ax² − 2ahx + (ah² + k). So b = −2ah and c = ah² + k. Switching the calculator to "Vertex form to standard form" does this for you and shows the steps.
Then the equation is linear, not quadratic: ax² + bx + c with a = 0 is just bx + c, a straight line with no vertex and no parabola. The calculator stops with an error explaining exactly this instead of printing a meaningless conversion.
The discriminant b² − 4ac classifies the intercepts before you compute them. If it is positive there are two x-intercepts, if zero there is exactly one and it sits at the vertex, and if negative the parabola never crosses the x-axis. The calculator reports all three cases in plain words.
The axis of symmetry is the vertical line x = h that cuts the parabola into two mirror halves. Every point on the parabola has a mirror twin across this line, so knowing it lets you sketch the whole curve from one side, and it is the line the vertex sits on.
Yes. Enter decimals freely, and the output shows 4 decimal places while the working steps show the exact fractions (for example 2 rather than 2.0000) wherever they come out clean. The two views let you read the answer and check the algebra at the same time.
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References
- Weisstein, E. W. Completing the Square, Wolfram MathWorld. Accessed October 23, 2026.
- Weisstein, E. W. Quadratic Equation, Wolfram MathWorld. Accessed October 23, 2026.
- Purplemath. The Vertex of a Parabola: Converting Vertex Form to Standard Form. Accessed October 23, 2026.
- OpenStax. College Algebra 2e (quadratic functions and completing the square). Accessed October 23, 2026.
- Paul Dawkins, Lamar University. Algebra/Trig Review: Graphing Parabolas by Completing the Square. Accessed October 23, 2026.
